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Solution for 531219 ÷ 579 - with remainder
Step 1Long division works from left to right. Since 579 will not go into 5, a grey 0 has been placed over the 5 and we combine the first two digits to make 53. In this case, 53 is still too small. A further 0 is added above 3 and a third digit is added to make 531. Note the other digits in the original number have been turned grey to emphasise this. The closest we can get to 531 without exceeding it is 5211 which is 9 × 579. These values have been added to the division, highlighted in red. |
| | | 0 | 0 | 0 | 9 |
|
| rem 276 |
| 579 | | 5 | 3 | 1 | 2 | 1 | 9 | |
| | | 5 | 2 | 1 | 1 | | | |
|
579 × table | 1 × 579 = | 579 | 2 × 579 = | 1158 | 3 × 579 = | 1737 | 4 × 579 = | 2316 | 5 × 579 = | 2895 | 6 × 579 = | 3474 | 7 × 579 = | 4053 | 8 × 579 = | 4632 | 9 × 579 = | 5211 |
|
Step 2Next, work out the remainder by subtracting 5211 from 5312. This gives us 101. Bring down the 1 to make a new target of 1011. |
| | | | | | 9 |
|
| rem 276 |
| 579 | | 5 | 3 | 1 | 2 | 1 | 9 | |
| | | 5 | 2 | 1 | 1 | | | |
| | | | 1 | 0 | 1 | 1 | | |
|
579 × table | 1 × 579 = | 579 | 2 × 579 = | 1158 | 3 × 579 = | 1737 | 4 × 579 = | 2316 | 5 × 579 = | 2895 | 6 × 579 = | 3474 | 7 × 579 = | 4053 | 8 × 579 = | 4632 | 9 × 579 = | 5211 |
|
Step 3With a target of 1011, the closest we can get is 579 by multiplying 579 by 1. Write the 579 below the 1011 as shown. |
| | | | | | 9 | 1 |
| rem 276 |
| 579 | | 5 | 3 | 1 | 2 | 1 | 9 | |
| | | 5 | 2 | 1 | 1 | | | |
| | | | 1 | 0 | 1 | 1 | | |
| | | | | 5 | 7 | 9 | | |
|
579 × table | 1 × 579 = | 579 | 2 × 579 = | 1158 | 3 × 579 = | 1737 | 4 × 579 = | 2316 | 5 × 579 = | 2895 | 6 × 579 = | 3474 | 7 × 579 = | 4053 | 8 × 579 = | 4632 | 9 × 579 = | 5211 |
|
Step 4Next, work out the remainder by subtracting 579 from 1011. This gives us 432. Bring down the 9 to make a new target of 4329. |
| | | | | | 9 | 1 |
| rem 276 |
| 579 | | 5 | 3 | 1 | 2 | 1 | 9 | |
| | | 5 | 2 | 1 | 1 | | | |
| | | | 1 | 0 | 1 | 1 | | |
| | | | | 5 | 7 | 9 | | |
| | | | | 4 | 3 | 2 | 9 | |
|
579 × table | 1 × 579 = | 579 | 2 × 579 = | 1158 | 3 × 579 = | 1737 | 4 × 579 = | 2316 | 5 × 579 = | 2895 | 6 × 579 = | 3474 | 7 × 579 = | 4053 | 8 × 579 = | 4632 | 9 × 579 = | 5211 |
|
Step 5With a target of 4329, the closest we can get is 4053 by multiplying 579 by 7. Write the 4053 below the 4329 as shown. |
| | | | | | 9 | 1 | 7 | rem 276 |
| 579 | | 5 | 3 | 1 | 2 | 1 | 9 | |
| | | 5 | 2 | 1 | 1 | | | |
| | | | 1 | 0 | 1 | 1 | | |
| | | | | 5 | 7 | 9 | | |
| | | | | 4 | 3 | 2 | 9 | |
| | | | | 4 | 0 | 5 | 3 | |
|
579 × table | 1 × 579 = | 579 | 2 × 579 = | 1158 | 3 × 579 = | 1737 | 4 × 579 = | 2316 | 5 × 579 = | 2895 | 6 × 579 = | 3474 | 7 × 579 = | 4053 | 8 × 579 = | 4632 | 9 × 579 = | 5211 |
|
Step 6Finally, subtract 4053 from 4329 giving 276. Since there are no other digits to bring down, 276 is therefore also the remainder for the whole sum. So 531219 ÷ 579 = 917 rem 276 |
| | | | | | 9 | 1 | 7 | rem 276 |
| 579 | | 5 | 3 | 1 | 2 | 1 | 9 | |
| | | 5 | 2 | 1 | 1 | | | |
| | | | 1 | 0 | 1 | 1 | | |
| | | | | 5 | 7 | 9 | | |
| | | | | 4 | 3 | 2 | 9 | |
| | | | | 4 | 0 | 5 | 3 | |
| | | | | | 2 | 7 | 6 | |
|
579 × table | 1 × 579 = | 579 | 2 × 579 = | 1158 | 3 × 579 = | 1737 | 4 × 579 = | 2316 | 5 × 579 = | 2895 | 6 × 579 = | 3474 | 7 × 579 = | 4053 | 8 × 579 = | 4632 | 9 × 579 = | 5211 |
|
example 2: Solution for 4870 ÷ 42 - with remainder
Step 1
Long division works from left to right. Since 42 will not go into 4, a grey 0 has been placed over the 4 and we combine the first two digits to make 48. Note the other digits in the original number have been turned grey to emphasise this.
The closest we can get to 48 without exceeding it is 42 which is
1 × 42. These values have been added to the division, highlighted in red.
You will notice that the division is set out carefully with the digits in vertical columns. This is very important when you work them out by hand.
Step 2
Next, work out the remainder by subtracting 42 from 48. This gives us 6. Bring down the 7 to make a new target of 67.
The digit brought down and the new target have been highlighted in blue.
Step 3
With a target of 67, the closest we can get is 42 by multiplying 42 by 1. Write the 42 below the 67 as shown.
Step 4
Next, work out the remainder by subtracting 42 from 67. This gives us 25. Bring down the 0 to make a new target of 250.
Step 5
With a target of 250, the closest we can get is 210 by multiplying 42 by 5. Write the 210 below the 250 as shown.
| | | | 1 | 1 | 5 | rem 40 |
| 42 | | 4 | 8 | 7 | 0 | |
| | | 4 | 2 | | | |
| | | | 6 | 7 | | |
| | | | 4 | 2 | | |
| | | | 2 | 5 | 0 | |
| | | | 2 | 1 | 0 | |
Step 6
Finally, subtract 210 from 250 giving 40. Since there are no other digits to bring down, 40 is therefore also the remainder for the whole sum.
So 4870 ÷ 42 = 115 rem 40
| | | | 1 | 1 | 5 | rem 40 |
| 42 | | 4 | 8 | 7 | 0 | |
| | | 4 | 2 | | | |
| | | | 6 | 7 | | |
| | | | 4 | 2 | | |
| | | | 2 | 5 | 0 | |
| | | | 2 | 1 | 0 | |
| | | | | 4 | 0 | |
Solution: 4870 ÷ 42 = 115 r 40
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